NEW YORK--(BUSINESS WIRE)--Philadelphia is the United States’ most expensive destination to stay overnight in this Labor Day weekend. After comparing the hotel rates of 30 popular U.S. destinations, a new survey conducted by CheapHotels.org has come to this conclusion. The survey specifically looked at lodging costs over the Labor Day weekend period spanning August 30 to September 2 (Labor Day).
In Philadelphia this end-of-summer weekend, travelers will have to pay $250 per night for the cheapest available double room in a minimum 3-star hotel. That price tag is more than double what they would have to spend on a regular weekend. Only slightly less expensive are Atlantic City and Seattle, the two runners-up on the survey. There, rooms can be found for $246 and $244 per night, respectively, over the Labor Day weekend.
Rounding out the top four is Milwaukee at a per-night rate of $228. That figure represents a 125% price increase compared to regular rates. As a result, Wisconsin’s largest city ranks as the biggest rate hiker among all 30 destinations considered by the survey. Certainly Harley Davidson's 110th anniversary party, which takes place in Milwaukee over the Labor Day weekend, is contributing to the city’s high hotel rates.
The following table shows the 10 most expensive destinations in the United States for this year's Labor Day weekend. The prices shown reflect the daily rate for each destination's cheapest available double room (minimum 3-star hotel) for the holiday time period of August 30 through September 2.
1. Philadelphia $250
2. Atlantic City $246
3. Seattle $244
4. Milwaukee $228
5. Boston $209
6. Virginia Beach $202
7. Atlanta $182
8. Charleston $181
9. New York City $178
10. Pittsburgh $167
To see the survey's full rankings, visit www.cheaphotels.org/press/labor-day-2013.html.